Which of the following sets of quantum numbers is impossible for an electron?

  • A
    $n = 1, l = 0, m_l = 0, m_s = +\frac{1}{2}$
  • B
    $n = 9, l = 7, m_l = -6, m_s = -\frac{1}{2}$
  • C
    $n = 2, l = 1, m_l = 0, m_s = +\frac{1}{2}$
  • D
    $n = 3, l = 2, m_l = -3, m_s = +\frac{1}{2}$

Explore More

Similar Questions

Which of the following orbitals has a dumbbell shape?

Select the correct statements for quantum numbers.
$(i)$ Magnetic quantum number $(m_l)$ gives information about the spatial orientation of orbitals with respect to the standard set of coordinate axes.
$(ii)$ Electron spin quantum number is represented by '$s$' and has values of $\pm \frac{1}{2}$.
$(iii)$ Principal quantum number $(n)$ determines the size of the orbitals and also,to a large extent,the energy of the orbitals.

Difficult
View Solution

The correct electronic configuration for the ground state of silicon (atomic number $= 14$) is

What is the number of orbitals in the $2p$ and $3p$ subshells? Where are they located?

According to which principle is the electronic configuration of nitrogen $1s^2 2s^2 2p_x^1 2p_y^1 2p_z^1$ and not $1s^2 2s^2 2p_x^2 2p_y^1 2p_z^0$?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo